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On 2/12/2023 at 8:39 PM, Jackhartmann said:

To calculate the final temperature after thermal equilibrium is reached, we need to consider the heat exchange between the two pieces of bismuth. We can start by using the heat equation:

ΔQ = mcΔT

where ΔQ is the heat exchange, m is the mass, c is the heat capacity, and ΔT is the change in temperature.

We can first calculate the heat absorbed by the solid bismuth, which is given by:

ΔQ1 = mc1ΔT1 = (27.7 g)(26.3 J K–1 mol–1)(253 °C - Tf)

where Tf is the final temperature.

Next, we can calculate the heat released by the liquid bismuth, which is given by:

ΔQ2 = -mc2ΔT2 = -(277 g)(31.6 J K–1 mol–1)(Tf - 333 °C)

Since the two pieces of bismuth are in thermal equilibrium, the heat absorbed by the solid must be equal to the heat released by the liquid, so we can set ΔQ1 = ΔQ2:

(27.7 g)(26.3 J K–1 mol–1)(253 °C - Tf) = -(277 g)(31.6 J K–1 mol–1)(Tf - 333 °C)

Solving for Tf, we find:

Tf = (253 °C - 333 °C)(27.7 g)(26.3 J K–1 mol–1) / [(277 g)(31.6 J K–1 mol–1)] + 333 °C

Tf = 324.4 °C

So the final temperature after thermal equilibrium is reached is 324.4 °C.

:preach:

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On 2/12/2023 at 7:39 PM, Jackhartmann said:

To calculate the final temperature after thermal equilibrium is reached, we need to consider the heat exchange between the two pieces of bismuth. We can start by using the heat equation:

ΔQ = mcΔT

where ΔQ is the heat exchange, m is the mass, c is the heat capacity, and ΔT is the change in temperature.

We can first calculate the heat absorbed by the solid bismuth, which is given by:

ΔQ1 = mc1ΔT1 = (27.7 g)(26.3 J K–1 mol–1)(253 °C - Tf)

where Tf is the final temperature.

Next, we can calculate the heat released by the liquid bismuth, which is given by:

ΔQ2 = -mc2ΔT2 = -(277 g)(31.6 J K–1 mol–1)(Tf - 333 °C)

Since the two pieces of bismuth are in thermal equilibrium, the heat absorbed by the solid must be equal to the heat released by the liquid, so we can set ΔQ1 = ΔQ2:

(27.7 g)(26.3 J K–1 mol–1)(253 °C - Tf) = -(277 g)(31.6 J K–1 mol–1)(Tf - 333 °C)

Solving for Tf, we find:

Tf = (253 °C - 333 °C)(27.7 g)(26.3 J K–1 mol–1) / [(277 g)(31.6 J K–1 mol–1)] + 333 °C

Tf = 324.4 °C

So the final temperature after thermal equilibrium is reached is 324.4 °C.

I cheated the other day and asked ChatGPT, here's what it said. I have no clue what any of this means, I was a Comm major...

--------

To find the final temperature after thermal equilibrium is reached, we need to determine the heat exchanged between the two bismuth samples.

Let's first find the total heat absorbed by the solid bismuth:

ΔQ = m_s * CP_s * ΔT

where: m_s = 27.7 g = 0.0277 kg (mass of solid bismuth) CP_s = 26.3 J K^-1 mol^-1 (heat capacity of solid bismuth) ΔT = 333 - 253 = 80 K (change in temperature)

Plugging in these values, we get: ΔQ = 0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 1269.84 J

Next, we need to determine the heat absorbed by the liquid bismuth:

ΔQ = m_l * CP_l * ΔT

where: m_l = 277 g = 0.277 kg (mass of liquid bismuth) CP_l = 31.6 J K^-1 mol^-1 (heat capacity of liquid bismuth) ΔT = T_f - 333 = T_f - 333 (change in temperature, T_f is the final temperature after thermal equilibrium is reached)

Since the two bismuth samples are at thermal equilibrium, the heat absorbed by the solid bismuth must equal the heat released by the liquid bismuth:

0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 0.277 kg * 31.6 J K^-1 mol^-1 * (T_f - 333)

Dividing both sides by 0.277 kg * 31.6 J K^-1 mol^-1, we can solve for T_f:

T_f = (1269.84 J / 0.277 kg / 31.6 J K^-1 mol^-1) + 333 K = 340.93 K + 333 K = 674 K = 401 °C

So the final temperature after thermal equilibrium is reached is 401 °C.

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On 2/12/2023 at 11:22 PM, Jesse-Lee said:

I cheated the other day and asked ChatGPT, here's what it said. I have no clue what any of this means, I was a Comm major...

--------

To find the final temperature after thermal equilibrium is reached, we need to determine the heat exchanged between the two bismuth samples.

Let's first find the total heat absorbed by the solid bismuth:

ΔQ = m_s * CP_s * ΔT

where: m_s = 27.7 g = 0.0277 kg (mass of solid bismuth) CP_s = 26.3 J K^-1 mol^-1 (heat capacity of solid bismuth) ΔT = 333 - 253 = 80 K (change in temperature)

Plugging in these values, we get: ΔQ = 0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 1269.84 J

Next, we need to determine the heat absorbed by the liquid bismuth:

ΔQ = m_l * CP_l * ΔT

where: m_l = 277 g = 0.277 kg (mass of liquid bismuth) CP_l = 31.6 J K^-1 mol^-1 (heat capacity of liquid bismuth) ΔT = T_f - 333 = T_f - 333 (change in temperature, T_f is the final temperature after thermal equilibrium is reached)

Since the two bismuth samples are at thermal equilibrium, the heat absorbed by the solid bismuth must equal the heat released by the liquid bismuth:

0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 0.277 kg * 31.6 J K^-1 mol^-1 * (T_f - 333)

Dividing both sides by 0.277 kg * 31.6 J K^-1 mol^-1, we can solve for T_f:

T_f = (1269.84 J / 0.277 kg / 31.6 J K^-1 mol^-1) + 333 K = 340.93 K + 333 K = 674 K = 401 °C

So the final temperature after thermal equilibrium is reached is 401 °C.

One of the most important checks you can do in physics (or chemistry, the branch of physics where you might also find this question) is, does the answer make sense? Even if you are somewhat unfamiliar with Bismuth, as a solid and a liquid, if you made the mental change to ice and water, would it make sense that putting a block of ice in water would yield a sample of water (after the block melted) that was hotter than before adding the ice?, because that's the result you came up with...

you put a 253 degree C block into a 333 degree C bath and come out with...a 401 degree C bath?!?

These kinds of mistakes are the probably the ones I would grade most harshly, because your intuition should've affected your reasoning better. 

ChatGPT still wouldn't pass my class.

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On 2/12/2023 at 10:54 PM, PeterPark said:

One of the most important checks you can do in physics (or chemistry, the branch of physics where you might also find this question) is, does the answer make sense? Even if you are somewhat unfamiliar with Bismuth, as a solid and a liquid, if you made the mental change to ice and water, would it make sense that putting a block of ice in water would yield a sample of water (after the block melted) that was hotter than before adding the ice?, because that's the result you came up with...

you put a 253 degree C block into a 333 degree C bath and come out with...a 401 degree C bath?!?

These kinds of mistakes are the probably the ones I would grade most harshly, because your intuition should've affected your reasoning better. 

ChatGPT still wouldn't pass my class.

Yeah, that seemed kinda weird, but I also didn't really care to think about it all that much.

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On 2/11/2023 at 10:53 PM, Lazyboy said:

No, regardless of what anyone states here..

It's not, and the number of panels is irrelevant without context. Both 655 and 656 are clearly brief teasers.

Agreed, like Hulk 180, Amazing 299 , Avengers 195, Invincible Iron Man 7, New mutants 86, 656 is a last page reveal teasar. This should be 2nd appearance in cameo.

On 2/11/2023 at 11:27 PM, Corona smith said:

Five panels and he speaks is a first full to me. 


For grading companies, Although it is an appearance, shadows of the character being in background and  body parts do not count towards a full appearance. The Scott Lang test is the bare minimum to qualify for full. Outside of the comic world, yes you would be correct. there would be no "1st appearance in cameo". However,remember we are using how CGC, the grading comic book world normally determines the type of 1st appearance is important.

Plus when you read 657, Batman litterally Introduces Daimen name for the 1st time with the name being in bold and  explains his origin to the reader. 657 should be 1st appearance in full.

Edited by catch21
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On 2/13/2023 at 6:40 AM, catch21 said:

Agreed, like Hulk 180, Amazing 299 , Avengers 195, Invincible Iron Man 7, New mutants 86, 656 is a last page reveal teasar. This should be 2nd appearance in cameo.


For grading companies, Although it is an appearance, shadows of the character being in background and  body parts do not count towards a full appearance. The Scott Lang test is the bare minimum to qualify for full. Outside of the comic world, yes you would be correct. there would be no "1st appearance in cameo". However,remember we are using how CGC, the grading comic book world normally determines the type of 1st appearance is important.

Plus when you read 657, Batman litterally Introduces Daimen name for the 1st time with the name being in bold and  explains his origin to the reader. 657 should be 1st appearance in full.

Five panels including a full page where he speaks isn’t a brief appearance. 

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On 2/13/2023 at 6:40 AM, catch21 said:

Agreed, like Hulk 180, Amazing 299 , Avengers 195, Invincible Iron Man 7, New mutants 86, 656 is a last page reveal teasar. This should be 2nd appearance in cameo.


For grading companies, Although it is an appearance, shadows of the character being in background and  body parts do not count towards a full appearance. The Scott Lang test is the bare minimum to qualify for full. Outside of the comic world, yes you would be correct. there would be no "1st appearance in cameo". However,remember we are using how CGC, the grading comic book world normally determines the type of 1st appearance is important.

Plus when you read 657, Batman litterally Introduces Daimen name for the 1st time with the name being in bold and  explains his origin to the reader. 657 should be 1st appearance in full.

New Mutants 86 isn't quite like the others. The "teaser" is more of an ad, as it's not in-story, just an image of Cable at the bottom of the final page, after the story content.

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On 2/13/2023 at 9:40 AM, troy.division said:

(full disclosure, I have two raw copies of 'Butterfly' #1 from an old DCBS order getting ready to send to CGC)

Honest questions -
What the heck is up with the asking prices on eBay?
Is the stated print run accurate?

It probably depends on who is stating what the print run is.

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On 2/13/2023 at 3:56 AM, Corona smith said:

Five panels including a full page where he speaks isn’t a brief appearance. 

 

On 2/13/2023 at 3:56 AM, Corona smith said:

Five panels including a full page where he speaks isn’t a brief appearance. 

All you are doing is repeating yourself without backing up with resources that show someone in the shadows and body count as full appearance in the grading community.  For example, Doomsday had multiple appearances with body parts only but those appearances  didn't count as full.  Hope pym appearance was just a leg soeaking and it didn't count as a full.

Edited by catch21
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On 2/13/2023 at 5:47 AM, GeeksAreMyPeeps said:

New Mutants 86 isn't quite like the others. The "teaser" is more of an ad, as it's not in-story, just an image of Cable at the bottom of the final page, after the story content.

Oh yeah that metal body at the end who speaks is Stryfe not Cable?

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On 2/10/2023 at 3:33 PM, gradejunky said:

Oh, nothing too difficult.  Although earlier today, I was pondering this as I walked to the mailbox:

Suppose a piece of solid bismuth weighing 27.7 g at a temperature of 253 °C is placed in 277 g of liquid bismuth at a temperature of 333 °C. Calculate the temperature after thermal equilibrium is reached, assuming no heat loss to the surroundings. The enthalpy of fusion of solid bismuth is ΔHfus = 11.0 kJ mol–1 at its melting point of 271 °C, and the molar heat capacities CP of solid and liquid bismuth are 26.3 and 31.6 J K–1 mol–1, respectively.

 

I was told there would be no math.

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On 2/13/2023 at 5:56 AM, Corona smith said:

Five panels including a full page where he speaks isn’t a brief appearance. 

Yes, it is.

Here is a perfect example of a cameo (a brief appearance by an established character):

SupesCameo.thumb.jpg.57b78d452952c8923bf222df05c20eba.jpg

The only reason Damian is called a brief appearance rather than a cameo (or two) is because new characters can't make cameos.

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On 2/13/2023 at 5:40 AM, catch21 said:

For grading companies, Although it is an appearance, shadows of the character being in background and  body parts do not count towards a full appearance. The Scott Lang test is the bare minimum to qualify for full. Outside of the comic world, yes you would be correct. there would be no "1st appearance in cameo". However,remember we are using how CGC, the grading comic book world normally determines the type of 1st appearance is important.

If grading companies want to do stupid things, that's on them. But that has nothing to do with the hobby, literacy, or intelligence. Brief/full appearances have nothing to do with how much/what parts of the character the artist draws, though it's certainly not unheard of for first brief appearances to be mysterious in some way.

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On 2/13/2023 at 6:40 AM, troy.division said:

(full disclosure, I have two raw copies of 'Butterfly' #1 from an old DCBS order getting ready to send to CGC)

Honest questions -
What the heck is up with the asking prices on eBay?
Is the stated print run accurate?

limited supply for the demand that outweighs it

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