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Jesse-Lee

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Everything posted by Jesse-Lee

  1. There are 36 on the census, just fyi. I'm not claiming it's not rare, and I'd personally be happy enough to own a .5 like this for the right price, but the "only one in circulation" language is a bit strange.
  2. It's like trying to time any market - the prevailing wisdom is don't try to time it. On a "blue chip" like ASM 129, you could use the stock market adage that "now is the best time to buy," meaning that blue chip investments that are bought and held on a long term should continue to appreciate over time. You may buy now for $2k, and it goes down to $1,700 in 3 months, but in 3 years it may be at $2,800; or it never dips, and you keep waiting for it to dip until you're either priced out or paying a premium for waiting. Comics are like other "investments" in the sense they go up and down, so the bigger question is, are you comfortable spending $2k on a 129 7.5, and is it something you plan to hold in your PC for the next 5, 10, 20 years? If so, what's the real value of potentially saving $300 (or not) in the short term vs securing the book now? I.e., in 20 years, will you really care about those $300?
  3. One of the major issues with eBay that I don't know how you'd fix it is that people don't seem to read anymore - I feel like this is a newer trend (not based on age, but based on how we're all fed and receive info now), because I see this at work a lot too. I carefully detail any flaws in the books I'm selling, both in pictures and in the text description, but I still get messages like "hey, is that a spine tic above the top staple?" Yes, it is - hence the "spine tic above top staple, soft corner on lower right" etc. details I added and the close-up photo. I'll also combine shipping and specify that if you buy multiple items you should ask for a combined invoice, but I still get people who will buy 3 books, pay for them with the shipping on all of them, and then message asking for a refund for shipping.
  4. The amount of times I've seen those books and passed on them because "I already have a copy of those" and "I'll find something better to spend $3 each on..."
  5. That's the biggest turn-off. People are ready for the Gunn era, to the point where people online are giving Gunn props for this movie finally coming out. But it won't be a Gunn movie, it'll be more of the same Snyderverse carp that has plagued the past decade of the majority of DC films. It's too bad they couldn't have afforded to scrap this one and start clean without it.
  6. I keep lucking out and running across these Innovation Nightmares on Elm Street for cheap - I'll take 'em! Picked up the first preview of W0rldtr33: And then a bunch of new release homage covers, because I'm a sucker for those:
  7. I want to get excited for this movie, but I just can't. Ezra Miller is such an awful Barry Allen, and this trailer just reminds me of more of the same from the recent (i.e., post-Nolan) DC movies. More Zod (blech), more Bat-fleck (also blech), more of the same aesthetic. Supergirl could be interesting I guess, but I don't love the direction they took with her based on the brief amount we see in the trailer. I have a soft spot for Keaton Batman, but even that just feels gimmicky. I can't wait to put the Snyderverse in the rear view mirror.
  8. Yeah, that seemed kinda weird, but I also didn't really care to think about it all that much.
  9. I cheated the other day and asked ChatGPT, here's what it said. I have no clue what any of this means, I was a Comm major... -------- To find the final temperature after thermal equilibrium is reached, we need to determine the heat exchanged between the two bismuth samples. Let's first find the total heat absorbed by the solid bismuth: ΔQ = m_s * CP_s * ΔT where: m_s = 27.7 g = 0.0277 kg (mass of solid bismuth) CP_s = 26.3 J K^-1 mol^-1 (heat capacity of solid bismuth) ΔT = 333 - 253 = 80 K (change in temperature) Plugging in these values, we get: ΔQ = 0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 1269.84 J Next, we need to determine the heat absorbed by the liquid bismuth: ΔQ = m_l * CP_l * ΔT where: m_l = 277 g = 0.277 kg (mass of liquid bismuth) CP_l = 31.6 J K^-1 mol^-1 (heat capacity of liquid bismuth) ΔT = T_f - 333 = T_f - 333 (change in temperature, T_f is the final temperature after thermal equilibrium is reached) Since the two bismuth samples are at thermal equilibrium, the heat absorbed by the solid bismuth must equal the heat released by the liquid bismuth: 0.0277 kg * 26.3 J K^-1 mol^-1 * 80 K = 0.277 kg * 31.6 J K^-1 mol^-1 * (T_f - 333) Dividing both sides by 0.277 kg * 31.6 J K^-1 mol^-1, we can solve for T_f: T_f = (1269.84 J / 0.277 kg / 31.6 J K^-1 mol^-1) + 333 K = 340.93 K + 333 K = 674 K = 401 °C So the final temperature after thermal equilibrium is reached is 401 °C.
  10. It was until Morrison made it canon. I was just goofing though, I wouldn't consider it his first appearance - although it is a fun read.
  11. You should hold on to this one, I could see it going... To the moon...